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/* Modeling an FMCW System with Sawtooth Modulation */
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Using the equations given at the beginning of this tutorial lesson, you can will find the range of your target:to be 1.5km, you would have expected from your specified delay of 10&mu;s.
<math> R = \frac{cT_s}{2B} f_b = \frac{(3\times 10^8)(100\times 10^{-6})}{2(10\times 10^6)} \left( 10^6 \right) = 1500\text{m} </math>
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